Figure shows a conductor of square loop placed parallel to the pole - faces of a ring magnet. The pole faces have an area of $1 c m^{2}$ each and the field between the poles is 0.1 T. the wires making the loop are all outside the magnetic field. If the magnetic field is removed in 1.0 s then the average emf induced in the loop is

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$12 μ V$

$15 μ V$

$10 μ V$

$5 μ V$

answer is B.

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Detailed Solution

Given that B 0.1T

$△ t = 1 s$

$△ A = 1 c m^{2} = 10^{- 4} m$

emf = $B \frac{d A}{d t} = 10^{- 1} \times \frac{10^{- 4}}{1} = 10^{- 5} \Rightarrow 10 \times 10^{- 6} \Rightarrow 10 μ ν$

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