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Figure shows a cylindrical conductor of length $l$ and area of cross section A. Its conductivity changes with distance (x) from one of its end as $σ = σ_{0} \frac{l}{x}$ ( $σ_{0}$ is a constant). A cell of emf V is connected across its ends. The electric field as a function of x is

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$\frac{2 V x}{l^{2}}$

$\frac{V x}{2 l^{2}}$

$\frac{V x}{l^{2}}$

$\frac{4 V x}{l^{2}}$

answer is C.

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