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Q.

Figure shows a loop ABCD carrying a current I is placed in a plane normal to a long wire carrying a current $I_{0}$ placed at point ‘O’ as shown. Find torque acting on the loop due mag field of long wire

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a

$τ = \frac{μ_{0} I_{0} I \sin θ}{π} (b - a)$

b

$τ = \frac{μ_{0} I_{0} I \sin θ}{2 π} (b - a)$

c

$τ = \frac{μ_{0} I_{0} I \sin \frac{θ}{2}}{π} (b - a)$

d

$τ = \frac{μ_{0} I_{0} I \sin θ}{4 π} (b - a)$

answer is C.

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Detailed Solution

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$d τ = d F 2 x \sin θ / 2$

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