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Q.

Figure shows a particle sliding on a frictionless track which terminates in a straight horizontal section. If the particle starts slipping from the point A, how far away from the track will the particle hit the ground?

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a

10m

b

0.1m

c

0.01m

d

1m

answer is A.

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Detailed Solution

$\begin{array}{l} mgH = \frac{1}{2} {mv}^{2} + mgh \\ particle will leave the track with a speed v = \sqrt{9 .8} m / s \end{array}$

Range $R = u \sqrt{\frac{2 h}{g}} = \sqrt{9 .8} \sqrt{\frac{2 (0 .5)}{9 .8}} = 1 m$

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