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Q.

Figure shows a regular pentagon with all its vertices on the sides of a rectangle . If BC = 14, calculate the perimeter of the pentagon .


C:UsersuserAppDataLocalMicrosoftWindowsINetCacheContent.Worded1b6301-4eed-4f9c-b6ec-6570aa31ab033573014692444065861.jpeg

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a

 0.31

b

 0.62

c

 0.77

d

1.00  

answer is C.

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Detailed Solution

Concept- Using the sine rule
asin A =bsin B=csin C , when a , b and c are the length of sides of the triangle and A, B,and C are the angles opposite to that sides a,b and c respectively .assume the length of one the sides of pentagon as x. we will use the sine rule to determine the value of x  and we will multiply this value with 5 to find  the perimeter.
All sides of the regular pentagon are equal. Assuming each side as x. name the pentagon MNOPQ. Now join the vertices N and Q to form a triangle . MNQ . also there , a rectangle  BNQC formed.
C:UsersuserAppDataLocalMicrosoftWindowsINetCacheContent.Worda46cc23b-3ccf-446c-bc2c-0f0cc7d3c3151661398243084875650.jpeg NQ=BC=14  since they are the opposite sides of rectangle BNQC
In triangle MNQ
Angle NMQ=108°, all internal angles of a regular pentagon is 108°.
MN=MQ,
angle MNQ=Angle MQN=36°
Apply sine rule in triangle in MNQ
MNsin 36° =NQsin 108° 
NQ=BC=14 we get
MNsin 36°=NQsin 108° 
xsin 36° =14sin 108° 
Using the conclusion,
sin 108°=sin 180°-108°=sin 72° and   
sin 2x=2sin xcos x , we get   
x=sin 36° 4×2sin 36°cos 36°  
x=18×cos 36° 
Substituting , Cos 36°=5+14, we get
x=18×5+14
x=12×15+1
Rationalise denominator.
x=12×15+×5-15-1
=12×5-15-1
=5-18
5=2.236
x=2.236-18
x=1.2368
x=0.1545
Perimeter of the pentagon =5x because all 5 sides are equal.
perimetre=5×0.1545=0.77
Hence, option (3) is the correct answer.
 
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