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Figure shows a rod PQ of length 20.0 cm and mass 200 g suspended through a fixed point O by two threads of lengths 20.0 cm each. A magnetic field of strength 0.500T exists in the vicinity of the wire PQ as shown in the figure. The wires connecting PQ with the battery are loose and exert no force on PQ. A current of 2.0 A is established when the switch S is closed. Find the tension in the threads now.

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4.21 N

1.25 N

6.23 N

2.92 N

answer is A.

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Detailed Solution

$2T \cos θ /2 = mg + F_{B}$

$2 T \cos 30 ° = mg + B i l$

$T = \frac{1}{\sqrt{3}} (2 + 0.2)$

$T = 1.25 N$

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