Figure shows a wooden block at rest in equilibrium on a rough horizontal plane being acted upon by forces ${\mathrm{F}}_1=10 \mathrm{N}$, ${\mathrm{F}}_2=2 \mathrm{N}$ as shown. If F₁ is removed, the resultant force acting on the block will be

The driving force on the block

              ${\mathrm{F}}_1-{\mathrm{F}}_2=10-2=8\mathrm{N}$

As the block is at rest the friction will be static and towards left.

             $\mathrm{f}={\mathrm{f}}_{\mathrm{s}}=8\mathrm{N}$

If F₁ is removed only F₂ = 2 N is acting on the block.

 If the block is at rest $\mathrm{f}={\mathrm{F}}_2=2 \mathrm{N}$ this value of friction is within static range as in previous case even f = 8 N is static case.