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Q.

Figure shows a Young's double slit experiment setup. The source S of wavelength 4000  oscillates along y-axis according to the equation y=sinπt, where y is in millimeters and t is in seconds. The distance between two slits S1 and S2 is 0.5 mm.

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a

The position of the central maxima as a function of time is 8 sin πt

b

The instant at which maximum intensity occurs at P for first time is 1π sin1 5480

c

The instant at which maximum intensity occurs at P for first time is 1π sin1 2780

d

The position of the central maxima as a function of time is 4 sin πt

answer is B, C.

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Detailed Solution

For central maxima path difference is zero 

        yd1+y1d4=0y1=y(4/1)=4 sin πt

For maximum intensity, yd1+ypd4=

For first time (n = 1),

yd+d28=λ

Solving t=1πsin15480

For minimum intensity, yd1+ypd4=n+12λ

For first time n = 1

        yd+d28=λ2

Solving t=1πsin12780

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