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Q.

Figure  shows   ABCDEF as  a  regular  hexagon with six vectors arranged in cyclic order  What  is  the  value of   AB¯+AC¯+AD¯+AE¯+AF¯

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a

6AO¯

b

AO¯

c

4AO¯

d

2AO¯

answer is D.

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Detailed Solution

AB+AC+AD+AE+AF=AB+(AB+BC)+(AB+BC+CD)+(AF+FE)+AF=6AO

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