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Q.

Figure shows an electric line of force which curves along a circular arc. The magnitude of electric field intensity is same at all points on this curve and is equal to E. If the potential at A is V, then the potential at B is :

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a

V + ER $θ$

b

V – E2R sin $\frac{θ}{2}$

c

V + E2R sin $\frac{θ}{2}$

d

V – ER $θ$

answer is A.

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Detailed Solution

$V_{A} - V_{B} = \int Edl = E \int dl = ERθ$ ,

As the line of force will be in the direction of decreasing potential.

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Figure shows an electric line of force which curves along a circular arc. The magnitude of electric field intensity is same at all points on this curve and is equal to E. If the potential at A is V, then the potential at B is :