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Q.

Figure shows an elevator and blocks A and B. The block A has mass m and block B has mass M. If the elevator is descending will an acceleration a, the force exerted by block A on block B is

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a

M(M+m)(g+a)

b

M(g+a)

c

m(g-a)

d

m(M+m)(g-a)

answer is C.

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Detailed Solution

Let R be the force exerted by A on B. The free-body diagrams are (since B applies an equal and opposite force R on A) as shown in Fig.

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For block A: mg –  R = ma 

R = m (g – a) 

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