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Q.

Figure shows an indicator diagram. During path 1-2-3 , 100 cal of heat  is given to the system and 40 cal work is done by the system. During path 1-4-3 work done is 10 cal.

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a

Heat given to the system during path 1-4-3 is 70 cal

b

If the system is brought from 3 to 1 along straight line path 3-1, work done by the system  is 25 cal

c

Along straight line path 3-1, the heat ejected by the system is 85 cal

d

The internal energy of the system in state 3 is 140 cal above that in state 1 .

answer is A, C.

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Detailed Solution

Q123=100 , W123=40 W143=10

Hence

U3-U1=100-40=60 cal  Q143=60+10=70 cal W31=-[10+40-102]=-25 cal Q31=-25-60=-85 cal

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