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Figure shows cross section of two large parallel metal sheets carrying electric currents along their surfaces. The current in each sheet is $\frac{10}{π} A/m$ along the sheet. Consider two points A and B, as shown in the figure with their positions.

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Magnetic field at A is

4 μ T

along x-direction

Magnetic field at A is

4 μ T

along negative x-direction

Magnetic field at B is

4 μ T

Magnetic field at B is

2 μ T

along x-direction.

answer is A.

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Detailed Solution

B due to a plane sheet is

$B = \frac{μ_{0} λ}{2}$ In depend of distance

At A $B_{A} = B_{1} + B_{2}$

$= \frac{μ_{0} λ}{2} + \frac{μ_{0} λ}{2}$

$B_{A} = μ_{0} λ$

$= 4 π \times 10^{- 7} \times \frac{10}{π}$

$= 4 \times 10^{- 6} = 4 μ T$

At B $B_{B} = B_{1} - B_{2} = 0$

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