Figure shows in cross section a wall consisting of four layers with thermal conductivities . $K_{1} = 0.06 W / mK; K_{2} = 0.04 W / mK and$
$K_{4} = 0.10 W / mK .$ The layer thicknesses are $L_{1} = 1.5 cm, L_{2} = 2.8 cm and L_{4} = 3.5 cm .$ . The temperature of interfaces is as shown in figure. Energy transfer through the wall is in steady state.
The temperature of the interface between layers 2 and 3 is

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11°C

8°C

7.2°C

5.4°C

answer is A.

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Detailed Solution

In steady state , rate of heat flow through layer 1= rate of heat fiow through layer 2.

$\Rightarrow \frac{0.06 \times A \times 5}{1.5 \times 10^{- 2}} = \frac{0.04 \times A \times ∆ T}{2.8 \times 10^{- 2}}$

$∆ T = 14 ° C$

$T_{3} = {(25 - 14)}^{0} c = 11 ° C$

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