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Q.

Figure shows (only cross section) a wooden cylinder C with a mass m of  0.25 kg, a radius R and a length l  perpendicular to the plane of paper of 0.1 meter with N=10  where N  is number of turns of wire wrapped around it longitudinally, so that the plane of the wire loop contains the axis of the cylinder. The least current through the loop is P2A  that will prevent the cylinder from moving down a plane whose surface is inclined at angle  θ  to the horizontal, in the presence of a vertical field of magnetic induction 0.5 weber/meter2 , if the plane of the windings is parallel to the inclined plane? (bottom most point of cylinder does not slip) then find value of P.

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answer is 5.

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Detailed Solution

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M=L×2R×i MBsinθ=mgsinθ R i=mg2BNI=2.5 A

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