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Figure shows that particle A is projected ,from point P with velocity u along the plane and simultaneously another particle B with velocity v at an angle $α$ with vertical. The particles collide at point Q on the plane. Then

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$vcos (α - θ_{0}) = u$

$v = u$

$vsin (α - θ_{0}) = u$

None of these

answer is A.

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Detailed Solution

If the particles collide at Q, it means they travel same displacement along the plane in same time. So their P velocity components along the plane should be same.

$vcos (β + θ_{0}) = u$
and $β = 90^{\circ} - α$
Solve to get v $\sin (α - θ_{0}) = u$

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