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Q.

Figure shows the adiabatic curve for n moles of an ideal gas; the bulk's modulus for the gas corresponding to the point P will be

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a

nR(1+T02V0)

b

nR(1+2T0V0)

c

nR(1+T0V0)

d

nR(2+T0V0)

answer is C.

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Detailed Solution

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Bulk's modulus K = -dPdVV = γP [PVγ = constant]

For the curve TVγ-1 = k (constant)

or V dT + T(γ-1)dV = 0

or dVdT = -V(γ-1)T = -1       (slope at point P)

 γ = 1+V0T0

 K = γ[nRT0V0] = nR(1+T0V0)

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Figure shows the adiabatic curve for n moles of an ideal gas; the bulk's modulus for the gas corresponding to the point P will be