Q.

Figure shows the graph of stopping potential versus the frequency of radiation incident on a photosensitive metal. Threshold frequency of the metal is

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a

(V2v2+V1v1)V2+V1

b

(V2v1+V1v2)V2+V1

c

(V2v1V1v2)ev2v1

d

(V2v1V1v2)V2V1

answer is D.

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Detailed Solution

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Ve=hυ+hυ0

V1e=hυ1hυ0  ______(1)         V2e=hυ2hυ0  ______(2)           (1)(2)V1V2=υ1υ0υ2υ0(υ2υ0)V1=(υ1υ0)V2       υ0=V2v1V1v2V2V1

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Figure shows the graph of stopping potential versus the frequency of radiation incident on a photosensitive metal. Threshold frequency of the metal is