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Figure shows the net power dissipated in R versus the current in a simple circuit. Then

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The internal resistance of battery is $0.2 Ω$ .

R at which power is 5W is $2.5 Ω$

At i= 2A, power is 3.2 W

The emf of battery is 2V

answer is A, B, D.

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Detailed Solution

At maximum power dissipation, $r = R$

So $i = \frac{E}{2 R} = 5 A$
And $i^{2} R = 5 W$
Solving $R = r = 0.2 Ω$
$E = 2 V$

Also at $i = 2 A$ ,

$P = i_{2} R$

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