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Q.

Figure shows three circular arcs, each of radius R and total charge as indicated. The net electric potential at the centre of curvature is 
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a

Q2πε0R

b

Qπε0R

c

Q4πε0R

d

2Qπε0R

answer is A.

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Detailed Solution

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V=V1+V2+V3  (all charges are the same distance R from the centre of curvature)

=14πε0QR+14πε0−2QR+14πε03QR

=14πε02QR

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