Figure shows two blocks A and B connected to an ideal pulley string system. In this system when bodies are released then :
(neglect friction and take $g = 10 m / s^{2}$ )

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Acceleration of block A is $1 m / s^{2}$

Acceleration of block A is $2 m / s^{2}$

Tension is string connected to block B is 40 N

Tension in string connected to block B is 80 N

answer is B, D.

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Detailed Solution

$a_{B} = 4 a_{A}, T = 10 a_{B} . . . . . . . (1)$

$40 g - 4 T = 40 a_{A} . . . . . . . (2)$

From (1) and (2)

$40 g = 4 (10 \times 4 a_{A}) + 40 a_{A} \Rightarrow 400 = 200 a_{A}$

$\Rightarrow a_{A} = 2 m / s^{2}$

T=80N.

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