Find 5x-22x-7=23x-1+72Subtopics: Laws of Exponents for Real Numbers

5x-22x-7=23x-1+725x-4x+14=43x-1+72x+14=12x-4+72x+14=12x+322x+14=12x+32x+28=12x+328-3=12x-2x25=10xx=2510=52

Find 5x-22x-7=23x-1+72Subtopics: Laws of Exponents for Real Numbers

5x-22x-7=23x-1+725x-4x+14=43x-1+72x+14=12x-4+72x+14=12x+322x+14=12x+32x+28=12x+328-3=12x-2x25=10xx=2510=52

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Find $5 x - 2 (2 x - 7) = 2 (3 x - 1) + \frac{7}{2}$

Subtopics: Laws of Exponents for Real Numbers

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\frac{1}{2}

\frac{5}{2}

answer is D.

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Detailed Solution

5 x - 2 (2 x - 7) = 2 (3 x - 1) + \frac{7}{2}

5 x - 4 x + 14 = \frac{4 (3 x - 1) + 7}{2}

x + 14 = \frac{12 x - 4 + 7}{2}

x + 14 = \frac{12 x + 3}{2}

2 (x + 14) = 12 x + 3

2 x + 28 = 12 x + 3

28 - 3 = 12 x - 2 x

25 = 10 x

x = \frac{25}{10} = \frac{5}{2}

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Find $5 x - 2 (2 x - 7) = 2 (3 x - 1) + \frac{7}{2}$

Subtopics: Laws of Exponents for Real Numbers