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Find an even $4$ digit number using $2, 7, 5, 1$ .

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7512

5217

7125

1275

answer is A.

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Detailed Solution

It is given that we have to find an even 4-digit number from the digits

2, 7, 5, 1

.
We know that an even number is an integer which is "evenly divisible" by two.
This means that if the integer is divided by

2

, it yields no remainder.
There are 4 possibilities of numbers from the given numbers.
(1)

7512

is divisible by

2

\frac{7512}{2} = 3756

, so it is a four digit even number.
(2)

5217

is not divisible by

2

, so it is not a four digit even number.
(3)

7125

is not divisible by

2

, so it is not a four digit even number.
(4)

1275

is not divisible by

2

, so it is not a four digit even number.
Hence,

7512

is a four digit even number using the digits

2, 7, 5, 1

.
The correct option is 1.

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Find an even $4$ digit number using $2, 7, 5, 1$ .