Find configuration which does not follow Hund's rule of maximum multiplicity for p-subshell.

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$\begin{aligned} 2 p_{x}^{1}, 2 p_{y}^{1}, 2 p_{z}^{1} \end{aligned}$

$\begin{aligned} 2 p_{x}^{2}, 2 p_{y}^{2}, 2 p_{z}^{2} \end{aligned}$

$\begin{aligned} 2 p_{x}^{1}, 2 p_{y}^{2}, 2 p_{z}^{0} \end{aligned}$

$\begin{aligned} 2 p_{x}^{2}, 2 p_{y}^{1}, 2 p_{z}^{2} \end{aligned}$

answer is C.

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Detailed Solution

According to Hund's rule of maximum multiplicity, an electronic configuration cannot couple up electrons in the p, d, and f orbitals until all of the orbitals in that subshell are filled with one electron or are solely occupied.

The s-orbital only has one orbital, hence it is not included in Hund's maximum multiplicity criterion. Only two electrons with opposite spins can fit within.

The maximum multiplicity criterion by Hund therefore says that
1. Before an orbital is double occupied in a sublevel, it is single-occupied.
2. The clockwise spin of the electrons in singly occupied orbitals is similar.

So, configuration which does not follow Hund's rule of maximum multiplicity for p-subshell $\begin{aligned} 2 p_{x}^{1}, 2 p_{y}^{2}, 2 p_{z}^{0} \end{aligned}$ .