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Q.

Find incorrect comparison of second ionization energy :

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a

In > Sr

b

Fe < Fe+

c

He > B

d

Te < Sb

answer is A.

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Detailed Solution

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(A) Valence shell electronic configuration of 'Te' = 5s25p4

       Valence shell electronic configuration of 'Sb' = 5s25p3 (stable configuration)

       Hence IP1 of Te < Sb

After removal of one electron, 'Te' acquires half filled configuration.

Hence IP2 of 'Te > Sb'

Hence Option(A) is the correct answer.

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Find incorrect comparison of second ionization energy :