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Find incorrect comparison of second ionization energy :

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An Intiative by Sri Chaitanya

In > Sr

Fe < Fe⁺

He > B

Te < Sb

answer is A.

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Detailed Solution

(A) Valence shell electronic configuration of 'Te' = 5s²5p⁴

Valence shell electronic configuration of 'Sb' = 5s²5p3 (stable configuration)

Hence IP₁ of Te < Sb

After removal of one electron, 'Te' acquires half filled configuration.

Hence IP₂ of 'Te > Sb'

Hence Option(A) is the correct answer.

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