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Q.

 Find maximum value of f(x)=1+sin2xcos2x4sin2xsin2x1+cos2x4sin2xsin2xcos2x1+4sin2x

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a

2

b

8

c

6

d

4

answer is C.

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Detailed Solution

  f(x)=1+sin2xcos2x4sin2xsin2x1+cos2x4sin2xsin2xcos2x1+4sin2x
Applying R2R2-R1 and R3R3-R1, then
f(x)=1+sin2xcos2x4sin2x-110-101
Applying C2C2+C1, then

f(x)=1+sin2x24sin2x-100-1-11
Expanding along R2, then
f(x)=24sin2x-11=2+4sin2x
   Maximum value of
f(x)=2+4(1) f(x)=6

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