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Find no .of compounds (s) in which atoms of anion are bounded by only one covalent bond $NaOH, {Na}_{2} O, {Na}_{2} O_{2}, {BaO}_{2}, {CaH}_{2}, {BaCl}_{2}, {Na}_{2} S_{2}$

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answer is 4.

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Detailed Solution

NaOH is ionic as NaOH has Na⁺ and OH^-.
Na₂O₂ is also ionic as Na₂O₂is $2 {Na}^{+} and O_{2}^{2 -}$ .
BaO₂ is also ionic as BaO₂ is ${Ba}^{2 +} and O_{2}^{2 -}$ .
Na₂S₂is also ionic as Na₂S₂ is $2 {Na}^{+} and S_{2}^{2 -}$ .

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