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Find out the current flowing through $4 Ω$ the resistor in the combination of the electric circuit given in the figure.

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1 A

2 A

3 A

None of the above

answer is A.

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Detailed Solution

The current flowing through

4 Ω

the resistor in the combination of the electric circuit given in the figure is

1 A

.
When two resistors are connected in parallel, their effective resistance is given by the formula,

\Rightarrow

\frac{1}{R_{p}} = \frac{1}{R_{1}} + \frac{1}{R_{2}}

(Where

R_{1}, R_{2}

are the resistances of two resistors in parallel)

\frac{1}{R_{p}} = \frac{1}{8} + \frac{1}{8}

\Rightarrow \frac{1}{R_{p}} = \frac{2}{8}

\Rightarrow \frac{1}{R_{p}} = \frac{1}{4}

R_{p} = 4 ohm

The total resistance in the circuit is,

R = R_{p} + 4

\Rightarrow 4 + 4

\Rightarrow 8 Ω

Current through the circuit is given by,

I = \frac{V}{R}

(Where

V

is voltage and

R

is resistance)

\Rightarrow \frac{8}{8}

\Rightarrow 1 A

Thus, the current through

4 Ω

1 A

4 Ω

, and

R_{p}

are in series and the same current flows through them.

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