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Q.

Find out the difference between the  number of angular nodes and number of radial nodes in the orbital to which last electron of chromium present.

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answer is 2.

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Detailed Solution

Last e– of Cr present in 3d
number of radial nodes = 3 – 2 – 1 = 0;
number of angular nodes = 2;
Difference = 2

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Find out the difference between the  number of angular nodes and number of radial nodes in the orbital to which last electron of chromium present.