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Q.

Find out the difference in number of angular nodes and number of radial nodes in the orbital to which last entering electron of chromium present.

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answer is 2.

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Detailed Solution

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Cr→3 d 5 4 s 1   No. of angular nodes = 2
No. of radial nodes = 3‐2‐1= 0
Angular node – radial node = 2
 
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