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Find range of the projectile along the inclined plane as shown in $(g = 10 m / s^{2})$

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39 m

35 m

40 m

45 m

answer is A.

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Detailed Solution

Given, $u = 20 \sqrt{2} m / s, α = 45 °, β = 30 °$

$R = \frac{u^{2}}{g \cos^{2} β} [\sin (2 α - β) - \sin β] = \frac{(20 \sqrt{2})^{2}}{(10) \cos^{2} 30 °} [\sin (2 \times 45 ° - 30 °) - \sin 30 °] ≅ 39 m$

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