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Find the acceleration of the block of mass M in the situation shown in the figure. All the surfaces are frictionless.

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$\frac{g}{5}$

$\frac{g}{2}$

$\frac{g}{3}$

$\frac{g}{4}$

answer is C.

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Detailed Solution

$T - M g \sin 30 ° = M a 2 M g - 2 T = 2 M (\frac{a}{2})$

Solving these equations, we get

$a = \frac{g}{3}$

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