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Q.

Find the angle which the straight line $y = \sqrt{3} x - 4$ markes with the y-axis.

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Detailed Solution

$Given line y = \sqrt{3} x - 4$
$slope m = \sqrt{3}$
$θ = 60^{\circ}$
given line makes an angle with y-axis is
$90^{0} - 60^{0} = 30^{0}$

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