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Find the angular elevation (angle of elevation from the ground level) of the sun When the length of the shadow of a30cm long pole is $10 \sqrt{3} m$ .

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60^{\circ}

59^{\circ}

58^{\circ}

55^{\circ}

answer is A.

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Detailed Solution

Suppose,

AB =

Pole

BC =

shadow,

∠ θ =

Angle of elevation from level of ground.
Question Image

△ ABC we have,

\tan c = \frac{perpendicular}{base}

\tan c = \frac{30}{10 \sqrt{3}}

\tan c = \sqrt{3}

\tan c = \tan 60^{o}

(Since,

\sqrt{3} = \tan 60^{0}

)

∠ c = 60^{0} = ∠ θ

(From alternate interior angles)
So, the angular elevation is

60^{0} .

So, option 1 is correct.

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