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Find the area of a quadrant of a circle whose circumference is 44 cm.

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38.5 {cm}^{2}

28.5 {cm}^{2}

58.5 {cm}^{2}

48.5 {cm}^{2}

answer is A.

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Detailed Solution

Given,
Circle circumference = 44 cm
Suppose R is the circle's radius.
We know that,
Radius of a circle's circumference

R = 2 πr

Here,

2 πr = 44

πr = \frac{44}{2}

r = \frac{22}{π}

r = \frac{22}{\frac{22}{7}}

r = 7 cm

Now,
Quadrant’s surface area

= \frac{1}{4} π r^{2}

= \frac{1}{4} \times \frac{22}{7} \times 7 \times 7

= \frac{77}{2}

= 38.5 {cm}^{2}

Thus, the required quadrant area is

38.5 {cm}^{2}

.
Correct option is 1.

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