Find the area of the shaded region in the figure given below Given that AC = 24cm, BC = 10cm, and O is the centre of the circle (Use 𝜋 =3.14)

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145.33 m2

145.33 cm2

145 m2

140 cm2

answer is B.

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Detailed Solution

Given AC= 24 cm
BC = 10cm
centre of circle = 0 Since, AOB is a night angle triangle. So, AC2 + BC2 = AB2 = 242 + 102 = AB2 = AB2 = 576 + 100 = 676 = AB = √676 = 26 cm
As the diameter of circle. So, AB = 2𝜋 = 26
=𝜋 = 26/2 = 13 cm
Area of triangle = ½ length . breath = ½ x 24x10 = 120 cm2 Area of circle = 𝜋r2 So, area of semicircle = 𝜋r2 /2 = 3.14x132 / 2 = 265.33 cm2 So, area of shaded region = 265.33 - 100 = 145. 33 cm2 Type- CBSE
Grade- 10
Subject- Mathematics
Chapter- Polynomials

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