Find the area of the shaded region in the following figure,

Given,
Circle’s Diameter D$=14\mathrm{ cm}$. 

Thus, its radius, $r=\frac{14}{2}=7\mathrm{ cm}\mathrm{ }$

Square’s side $a=4\mathrm{ cm}$
Quadrant angle, $\theta =\frac{\pi }{2}$
Now, the area of the circle can be given as
$A=\pi r^2$

$\begin{array}{c} A=\left(\frac{22}{7}\right)\times (7{)}^2\\ \end{array}$
$A=154{\mathrm{ cm}}^2$
Area of square part,
$A_s=(\mathrm{a}{)}^2$
$A_s=(4{)}^2$
$A_s=16{\mathrm{ cm}}^2$
Now, the area of the quadrant part,
$A_q=\frac{1}{4}\pi r^2$
$\begin{array}{c} A_q=\frac{1}{4}\times \left(\frac{22}{7}\right)\times (7{)}^2\\ \end{array}$
$A_q=38.5\mathrm{ }{\mathrm{cm}}^2$

Now, from the figure, 

the side of the small shaded square = 7 cm - 5cm = 2cm.
Area of the square of the side which has a 2 cm side$=2{\mathrm{cm}}^2=4{\mathrm{cm}}^2$
Let the area of the shaded region is $A_s$. 

Thus,
$A_s$= area of circle - area of square - area of quadrant + area of the square of side 2 cm
$$\begin{gathered} {\mathrm{A}}_{\mathrm{s}}=154-16-38.5+4 \\ {\mathrm{A}}_{\mathrm{s}}=103.5 {\mathrm{cm}}^2 \end{gathered}$$
Hence, option 103.5 cm² is correct.