Find the area of the trapezium, whose two parallel sides are 8.2 cm and 10 cm respectively. The distance between two parallel sides is 4 cm.

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36.4 cm²

36.2 cm²

36.5 cm²

36.8 cm²

answer is D.

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Detailed Solution

Given, the two parallel sides of the trapezium are 8.2 cm and 10 cm respectively.

The distance between two parallel sides (height) of the trapezium = 4 cm.

Sum of parallel sides of the trapezium = 8.2 + 10 = 18.2 cm.

Area of the trapezium = $\frac{1}{2}$ x (sum of parallel sides) x (height).

$\begin{array}{rcl} = & \frac{1}{2} \times (18.2) \times 4 \\ = & 36.4 {cm}^{2} \end{array}$

Therefore, the area of the trapezium is 36.4 cm².

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