Find the area of the triangle formed by the line $3\mathrm{x}-4\mathrm{y}+12=0$ with the coordinate axes.

$\text{ Given line }3\mathrm{x}-4\mathrm{y}+12=0$
$\mathrm{a}=3,\mathrm{b}=-4,\mathrm{c}=12$
$\text{ Area of the }{\mathrm{\Delta }}^{\mathrm{le}}\text{ made by the line with the }$$\text{ coordinate axes is }\frac{{\mathrm{c}}^2}{2\left|\mathrm{ab}\right|}$
$Area=\frac{(12{)}^2}{2|3\times -4|}=\frac{12}{2}=6\text{ sq. units }$