Find the area of the triangle formed by the lines representing the equations $2x-y-2=0$ and $4x-y-4=0$ with the y-axis. 

Given equations are: 

$2x-y-2=0 -----\left(1\right)$ 

$4x-y-4=0 -----\left(2\right)$ 

Table for the equation (1): 

$2x-y-2=0$ 

$y=2x-2$ 

Table for the equation (2): 

$4x-y-4=0$

$y=4x-4$  

Now plot all the points on the graph.

The triangle formed by the lines representing the equations $2x-y-2=0$ and $4x-y-4=0$ with the Y-axis is $△ABC$. 

Consider $△ABC$, 

AC is the base and BO is the altitude. 

$Area of △ABC=\frac{1}{2}\times AC\times BO$

$Area of △ABC=\frac{1}{2}\times 2\times 1$

$Area of △ABC=1 \mathrm{sq}.\mathrm{unit}$

Hence, the area of the triangle formed by the lines representing the equations $2x-y-2=0$ and $4x-y-4=0$ with the Y-axis is 1 sq.unit.