Find the area of the triangle formed by the straight line x – 4y + 2 = 0 with the coordinate axes.

The area of the triangle formed by st.line ax + by + c = 0 with co-ordinate axes is $\frac{{\mathrm{c}}^2}{2\left|\mathrm{ab}\right|}\mathrm{sq}.\mathrm{unit}. \mathrm{Given} \mathrm{line} \mathrm{x} – 4\mathrm{y} + 2 = 0$
$\therefore \mathrm{The} \mathrm{area} \mathrm{of} \mathrm{the} \mathrm{triangle} \frac{{\mathrm{c}}^2}{2\left|\mathrm{ab}\right|}$
$=\frac{2^2}{2\left|\right(1\left)\right(-4\left)\right|}=\frac{1}{2}\text{ sq. units }$