Q.

Find the area of the triangle formed by the straight line xcosα+ysinα=p and the coordinate axes.

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Detailed Solution

Given st.line xcosx+ysinα=p
The area of the triangle formed by line
ax+by+c=0 with co-ordinate axes is c22|ab|
=(p)22|cosαsinα|=p2|sin2α|=p2|cosec2α|

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