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Q.

Find the area of triangle whose vertices are 3,2, -2,-3 and (2,3).


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a

5sq unit  

b

3sq unit  

c

6sq unit  

d

4sq unit   

answer is A.

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Detailed Solution

Given vertices of the triangles are
3,2 , 2,3 , 2,3  .
We know that,
The area of a triangle, whose vertices are A x 1 , y 1 ,B x 2 , y 2 ,C x 3 , y 3   is given by ar ΔABC = 1 2 x 1 y 2 y 3 + x 2 y 3 y 1 + x 3 y 1 y 2 sq unit   .
Here,
  x 1 =3, x 2 =2, x 3 =2, y 1 =2, y 2 =3,and y 3 =3  .
Then,
ar ΔABC = 1 2 3 33 +(2) 32 +2 2(3) ar ΔABC = 1 2 182+10 ar ΔABC =5sq unit  
Therefore, the area of the triangle is 5 sq unit.
Hence, option (1) is correct.
 
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