Q.

We know that area of 1 square = 1 sq. unit

(a) The figure has nine squares in total.

Area of 9 squares = 9 × 1 sq. unit = 9 sq. units.

As a result, the given figure has a 9-square-unit area.

(b) The figure has 5 squares in total.

So, Area of 5 squares = 5 × 1 sq. unit = 5 sq. units

As a result, the given figure has a 5-square-unit area.

(c) The figure has 2 complete and 4 half squares in total.

So, Area of the figure = 2 × 1 + 4 × 1/2 = 2 + 2 sq. units

= 4 sq. units

As a result, the given figure has a 4-square-unit area.

(d) The figure has 8 squares in total.

So, Area of 8 squares = 8 × 1 sq. unit = 8 sq. units

As a result, the given figure has an 8-square-unit area.

(e) The figure has 10 squares in total.

So, Area of 10 squares = 10 × 1 sq. unit = 10 sq. units

As a result, the given figure has a 10-square-unit area.

(f) The figure has 2 complete and 4 half squares in total.

So, Area of the figure = 2 × 1 + 4 × 1/2 = 2 + 2 sq. units

= 4 sq. units

As a result, the given figure has a 4-square-unit area.

(g) The figure has 4 complete and 4 half squares in total.

So, Area of the figure = 4 × 1 + 4 × 1/2 = 4 + 2 sq. units

= 6 sq. units

As a result, the given figure has a 6-square-unit area.

(h) The figure has 5 squares in total.

So, Area of 5 squares = 5 × 1 sq. unit = 5 sq. units

As a result, the given figure has a 5-square-unit area.

(i) The figure has 9 squares in total.

So, Area of 9 squares = 9 × 1 sq. unit = 9 sq. units

As a result, the given figure has a 9-square-unit area.

(j) The figure has 2 complete and 4 half squares in total.

So, Area of the figure = 2 × 1 + 4 × 1/2 = 2 + 2 sq. units

= 4 sq. units

As a result, the given figure has a 2-square-unit area.

(k) The figure has 4 complete and 2 half squares in total.

So, Area of the figure = 4 × 1 + 2 × 1/2 = 4 + 1 sq. units

= 5 sq. units

As a result, the given figure has a 5-square-unit area.

(l) The figure has 3 complete, 4 greater than half, and 3 less than half squares in total.

So, Area of the figure = 3×1 + 4×1 + 3 × 0 = 3 + 4 + 0 sq. units

= 7 sq. units

As a result, the given figure has an 8-square-unit area.

(m) The figure has 7 complete, 5 greater than half, 5 less than half, and 1 exact half square in total.

So, Area of the figure = 7×1 + 5×1 + 5×0 + 1×1/2 = 7 + 5 + 0 + 0.5 = 12.5 sq. units

= 12.5 sq. units

As a result, the given figure has a 12.5 square-unit area.

(n) The figure has 10 complete, 3 greater than half, and 10 less than squares in total.

So, Area of the figure = 10×1 + 3×1 + 10×0 = 10 + 3 + 0 sq. units

= 13 sq. units

As a result, the given figure has a 13-square-unit area.