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Q.

Find the binding energy of an α-particle from the following data. Mass of He nucleus =4.001265 amu; Mass of proton=1.007277 amu; Mass of neutron=1.00866 amu (Take one amu =931.5 MeV)

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a

1850 MeV

b

296 MeV

c

28.512 MeV

d

None of these

answer is C.

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Detailed Solution

Mass defect: Δm=2mp+mn−mN=2(1.007277+1.00866)−4.001265=0.030609 amu

Binding energy=Δm×931.5MeV=0.030609×931.5=28.512 MeV

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