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Find the binding energy of an $α$ -particle from the following data. Mass of He nucleus =4.001265 amu; Mass of proton=1.007277 amu; Mass of neutron=1.00866 amu (Take one amu =931.5 MeV)

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28.512 MeV

1850 MeV

296 MeV

None of these

answer is C.

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Detailed Solution

Mass defect: $Δm = 2 (m_{p} + m_{n}) - m_{N} = 2 (1 .007277 + 1 .00866) - 4.001265 = 0 .030609 amu$

Binding energy $= Δm \times 931 .5 MeV = 0 .030609 \times 931 .5 = 28 .512 MeV$

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