Find the centre of mass of letter. F w.r.t. point $\mathrm{O}$. Which is cut from a uniform metal sheet?

$$\begin{gathered} m_1= \sigma \times 16, m_2= \sigma \times 8, m_3= \sigma \times 4 \\ {x}_c= \frac{m_1\times 1+ m_2\times 4+ m_3\times 3}{m_1+ m_2+ m_3}= \frac{60\sigma }{28\sigma }= \frac{15}{7} \\ {y}_c= \frac{m_1\times 4+ m_2\times 7+ m_3\times 3}{m_1+ m_2+ m_3}= \frac{132}{28}= \frac{33}{7} \end{gathered}$$