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Find the change in internal energy in joule. When 10g of air is heated from 30°C to 40°C (Cv = 0.172 kcal/kg K, J = 4200 J/kcal)

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62.24 J

72.24 J

52.24 J

82.24 J

answer is B.

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Detailed Solution

m = 10 × 10^–3kg

ΔT = T2 – T1 = 40 – 30 = 10^oC

Cv = 0.172k.cal/kg–k

${C_v} = frac{1}{m}frac{{{{(Delta Q)}_v}}}{{Delta T}}$ ; here (ΔQ)_v = ΔU

$therefore Delta u = m{c_v}Delta T$

$Delta U = 1cancel{0} times {10^{ - cancel{3}}} times 0.172 times 420cancel{0} times 1cancel{0} = 72.24J$

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