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Q.

Find the change in internal energy in joule.  When 10g of air is heated from 30°C to 40°C (Cv = 0.172 kcal/kg K, J = 4200 J/kcal)

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a

62.24 J   

b

72.24 J

c

52.24 J

d

82.24 J

answer is B.

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Detailed Solution

m = 10 × 10–3kg

ΔT = T2 – T1 = 40 – 30 = 10oC 

Cv = 0.172k.cal/kg–k 

{C_v} = frac{1}{m}frac{{{{(Delta Q)}_v}}}{{Delta T}}; here (ΔQ)v = ΔU

therefore Delta u = m{c_v}Delta T

Delta U = 1cancel{0} times {10^{ - cancel{3}}} times 0.172 times 420cancel{0} times 1cancel{0} = 72.24J

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