Q.

Find the change in pH when 0.01 mole CH3COONa is added to one litre of 0.01M CH3COOH solution (pKa = 4.74 )

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a

1.37

b

4.74

c

3.27

d

2.74

answer is C.

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Detailed Solution

PH of a 0.01 M CH3CHOOH solution = \frac{1}{2}\left[ {{P^{{K_a}}} - \log C} \right]

PH of a 0.01 M CH3CHOOH solution = \frac{1}{2}\left[ {4.74 + 2} \right]

PH of a 0.01 M CH3CHOOH solution = 3.37

PH of an acidic buffer = {P^{{K_a}}} + \log \frac{{\left[ {salt} \right]}}{{\left[ {acid} \right]}}

PH of an acidic buffer = {P^{{K_a}}} + \log \frac{{\left[ {salt} \right]}}{{\left[ {acid} \right]}}

                                        = 4.74 + \log \frac{{0.01}}{{0.01}}

                                        = 4.74

Thus, change in PH = 4.74 - 3.37 = 1.37

                                                                  

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