Find the complement of angles ${73}^{\circ }$.

Let, the measure of its complement be x.

Given, angle = 73^o

We know that, If two angles are complementary, then the sum of their measures is 90^o.
$\Rightarrow$ x + 73^o =  90° 
 $\Rightarrow$ x = (90 - 73 )° = 17°
$\therefore$ Thus, the complement of the given angle will be 17°.