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Find the complements of $68^{o}$ and $33^{o}$ respectively.

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22^{o}, 57^{o}

57^{o}, 22^{o}

33^{o}, 67^{o}

67^{o}, 33^{o}

answer is A.

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Detailed Solution

It is given the angles are,

68^{o}

and

33^{o}

. We need to find their complements.
We know that, two angles are complementary when they add up to

90^{o} .

Measure of one complementary angle is

68^{o} .

So the measure of the other complementary angle,

= 90^{o} - 68^{o}

= 22^{o}

∴

Measure of a complementary angle of

68^{o}

22^{o}

.
Also given measure of one complementary angle is

33^{o} .

Measure of other complementary angle

= 90^{o} - 33^{o}

= 57^{o}

∴

Measure of a complementary angle of

33^{o}

57^{o}

.
Therefore, option 1 is the right answer.

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